Hello All,
Lon the new, senior shooter here! I introduced myself in the appropriate forum a couple of months ago. I hesitated posting a question here on the above Dan Wesson, until I searched and saw several post on DW revolvers.
I went to a local gun shop and asked their reactions about the 715. Remember, I'm in California and have never bought a gun in my life; fired them, but never bought one.
Although they were complimentary about the 715, they came across as "damning with faint praise". The main drawback in their eyes was "the gap". They didn't make clear what the objection to this was, but were not encouraging me in the 715's direction. Wanted to show me their line of S&W semi-autos. In the past 2 years, all I've shot are revolvers; .38, .357 and .44 mag and I love them! I'm not considering a semi auto at the moment. Should I?
I was told that "if...if we could find a private party 715 in California it would be terribly expensive", although I've never once winced at pricing when it came to something I thought was worth the money.
Is it true that if I found a new/used 715 for, say $1,200 from a certified gun shop or private party in the U.S., I could not legally purchase it as a California resident? Must it be a
used 715 from within California only? Perhaps I misunderstood, but that's what it sounded like.
If not, would you please suggest a comparable .38/.357 for a first time buyer?
Second question. is there a website where I can learn the ins-and-outs of buying a revolver in California? Particularly, can I buy a used revolver from anywhere in the US, have it shipped to my local FFD as a legal purchase?
My #1 purchase remains the S&W 617-6 [SKU 160578], mentioned in my post in the introduction forum. I've checked and it is on the California A/G's list of acceptable purchase firearms.
http://certguns.doj.ca.gov/safeguns_resp.asp
Could I then, seek the best deal, wherever that may be [brick and mortar shop, Internet or private party], send it to the FFD, to make a legal purchase?
Many thanks for taking the time to respond!
Lon