How far is one complete revolution equal to on an N-frame revolver? I seem to recall from the dim, dusty recesses of my memory that it is 0.030 inches, but that may be incorrect. Please, O Great Gurus of Smith and Wesson minutia, give me the answer.

K, L and N frames are all 36 tpi so 0.0277". 0.030" was pretty good for memory.

J and X frames are probably the same but I'll leave them for the great gurus.