Since this is a New Thread I'd like to know size wise what the difference is between a model 360 and a model 60? Since I want to buy a holster online.
Also I have one of the 50 original 360s in 38 special, Since the last 3 digits in the serial number is 001 do I have the first one?

This is a J-Frame by the way. The Mods should know this before they moved it.

The difference that matters is weight .

The Model 60 is an all-stainless J-frame 357 Magnum, weighs 21.5 ounces empty.
The Model 360 is an Airweight J-frame 357 Magnum, scandium alloy frame, titanium alloy cylinder, stainless steel barrel, weighs 11.8 ounces empty.
Based on the recoil of my Model 640-1, an all-stainless J-frame, I think recoil with 357 Magnum rounds in an Airweight would be... "unpleasant".

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VCDL, GOA, NRA

I do not know if the thread was moved, but if it was it may have been because the model 360 has an unpinned barrel per the Revolvers 1980-Present title.

That said, there are several lengths and variations of model 60s and 360s. A holster made for an original J frame, 1.875" barrel model 60 may not fit a J Magnum (larger) frame model 360, some of which had a 2.125" barrel. Later J Magnum framed model 60s will use the same holsters as a model 360, maybe...

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Alan
SWCA LM 2023, SWHF 220

They are both J-frames and thus identical in terms of cylinder diameter and length. The frames are identical. The M60 is all-stainless whereas the M360 isn't.
I happen to own a Model 360 to which I fitted a Titanium cylinder bringing the weight down to 12.5 ounces.

Attached Images

	S&W360_357Mag horiz.jpg (31.7 KB, 12 views)
	S&W 360 PD conversion.jpg (141.6 KB, 11 views)
	S&W642_360_43C.jpg (64.4 KB, 10 views)