I'd really like to find out if the LEM would fire IF
-firing pin block was defeated
-internal "unseen" part of hammer gets released
I think we'd both agree that these guns are crazy safe. So many things have to be defeated that the guns simply won't fire without human intervention.
However, if the firing pin block was defeated and the main spring were released, rotating the inside hammer bushing, I'm 100% positive the gun wouldn't fire. There are two reasons for my confidence. The first is the simple fact that there isn't enough momentum in the internal bushing, without the hammer, to overcome the firing pin return spring, and send the firing pin into the primer with enough force to ignite it. The second is the aspect of the H&K USP you forgot, the hammer block.
The H&K USP LEM works like this:
When the gun is fired, the slide cocks the main spring. As the trigger is released, the hammer follows it down. There is a hammer block similar to the half-cock position on a 1911. This block keeps the hammer back about 1/16" from the firing pin. This gap will prevent the gun from firing even if the main spring were released.
So, for the H&K USP LEM to accidentally discharge, the sear would have to fail, the firing pin block would have to fail, the hammer block will have to fail and the force delivered to the firing pin will have to be enough to overcome the firing pin return spring.
Just to keep this on track, all of this has nothing to do with the terminology used to describe the trigger system. You may call it what you like.