Locked 627 in a aluminum performance center case

I'd agree with getting a locksmith and trying to get the seller to pay but expect he'd balk too.
I have one of those fireproof document cases that is locked and I think has papers from my late Father's estate. I can't find a key to fit and will try a locksmith too. I don't want to cut the locks as I'd like to reuse the case.
 
I'd agree with getting a locksmith and trying to get the seller to pay but expect he'd balk too.
I have one of those fireproof document cases that is locked and I think has papers from my late Father's estate. I can't find a key to fit and will try a locksmith too. I don't want to cut the locks as I'd like to reuse the case.

I've been to a couple of Michigan gun shows this year where a vendor was selling lock pick kits. PM me if you want his website info.
 
I've been to a couple of Michigan gun shows this year where a vendor was selling lock pick kits. PM me if you want his website info.

Contrary to popular belief and TV, buying a pickset isn't a guarantee that he will be successful. And in some states, they are illegal.

And if it uses a barrel type key he will need to see a locksmith.

If it's a $20 fire box, pry it open and then buy a new one.
 
You could always soot it open. What? Oh yeah the gun is locked inside.
I would have the dealer pry it open. Call the PC and ask for a new case, or, buy one on Ebay.
 
This was taught to me years ago: If this is a roller type combination lock try this; use a thin small screwdriver blade to hold the left most roller to the left. With good light behind you and a magnifying headset watch the gap between the roller and the right side of the opening for a small difference in appearance of the axis. When that is spotted leave that roller in that position and move to the next. Do the same examination all the way to the right positioning each roller where the anomaly in the axis of the roller appears. When all 3,4 or 5 of the rollers is so positioned, that should be the combination. This has worked for me several time on customer's problem lockable gun cases. A bank vault, they aint. .......
If the above doesn't open the lock, move the first roller one digit higher, then the next etc. Try that, if that doesn't work, go back to the original position all the way across and try one digit less all the way across. One of those three possible combination should work. .......
 
Jus' Thinkin':D;):D:eek::eek::eek::eek:

If order mattered, we would say select the first number (10 choices), then the second (9 choices) then the third (8 choices). So there would be 10 x 9 x 8 = 720 possible choices.
But because order does not matter, we have to take care of duplicates as you mentioned. How many duplicates are there for each set of three numbers? Well, again, we can choose one of the three as the "first", so there are 3 choices for that, then 2 choices for the "second" digit, then 1 choice for the last digit. There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits.
Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6.
720 / 6 = 120.
That's your answer.
These are what are mathematically called "combinations". You can use a formula involving factorials to determine the number of combinations.
In this case, we say this is "10 Choose 3" and write it as 10C3. That means from a set of ten (digits in
this case), choose 3 regardless of order.
The formula for nCm is
nCm = n! / [ m! x (n-m)!]
So in your question, we have
10C3 = 10! / [3! x (10-3)!] = 10! / [3! 7!]
= (10 x 9 x 8 x 7!) / [ (3 x 2 x 1) 7!]
= (720) / 6 ... because the 7! on the top and bottom cancels.
= 120 as we expected.

You said "factorials"! :eek: That is all, my head hurts...
 
Back
Top